Regex to find end of paragrphs -


i'm parsing text , paragraph breaks have been removed. need regex locate sentence ends in punctuation (period, question, etc) , there no space before next sentence starts. take , insert 2 linebreaks. unfortunately regex have far greedy , snagging on urls.

preg_replace('/(?<!\.)\.(?!(\s|$|\,|\w\.))/', '.<br/><br/> ', $string);

example text:

approved source xxxx xxx.the solicitation xxx , available @ link provided in notice. see http://www.mysite.com. hard copies of solicitation not available. specifications, plans, or drawings not available.all responsible sources may submit quote which, if timely received, shall considered.quotes must submitted electronically.

final desired result:

approved source xxx xxxx.

the solicitation xxx , available @ link provided in notice. hard copies of solicitation not available. see http://www.mysite.com. specifications, plans, or drawings not available.

all responsible sources may submit quote which, if timely received, shall considered.

quotes must submitted electronically.

thanks

(?<!w{3})[\.\?](?=\s)(?!com)

assuming urls start/end www. , .com, prevent matching, while retaining match on . , ? have non-whitespace after them. you'll have replace match .<br><br> though, not <br><br>.

play regex here.


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