bash - How to grep -o without the -o -


i've got busybox v1.01 providing commands. hence, -o not included in grep. how can grep -o behavior without ... -o?

if have sed can use simple regex. (see linuxquestions.org)

sed -n 's/.*\(pattern\).*/\1/p' file

so find text stackoverflow in file file.txt you'd write

sed -n 's/.*\(stackoverflow\).*/\1/p' file.txt

remember pattern in sed command regular expression. if pattern contains meta characters of regular expression, need escaped.


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